IUPAC name of the compound $C H_{2} = C H - C H O$ is:

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Solution

In the above compound $^{'} =^{'}$ and $^{'} - O ∥ C - H^{'}$ are present in the priority table $^{'} - O ∥ C - H^{'}$ is given first preference . So, the name is formed by changing the suffix $^{'} - e^{'}$ of the parent alkane to $^{'} - a l^{'}$
Prop represents no. of carbons double bond is present at $2 n d$ position . So $- 2 -$ ene.
In $- 2 -$ ene last $^{'} e^{'}$ is replaced by $- a l^{'}$ the suffix name of $^{'} - O ∥ C - H^{'}$ which is given first preference.

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C H_{3} - C H (C H_{3}) - C H (C H_{3}) - C H = C H - C H_{2} - C H O

C | C H O H_{2} C | C H O H - C | C H O H_{2}

\begin{matrix} C H_{3} - & C H & - C H_{2} - C H O | N H_{2} \end{matrix}

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