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Question


IUPAC name of the compound is:

A
Hex-1-ene-5-yne
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B
Hex-5-yne-1-ene
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C
Hex-1-en-5-yne
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D
None of the above
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Solution

The correct option is C Hex-1-en-5-yne
Theory :

Nomenclature of alkenyne :

If double and triple bond, both present in a structure with no other higher ranked substituent present:

Note :

While numbering - lowest locant set is chosen.

In case of a tie - Alkene is preferred over alkyne in assigning number

While naming - 'ene' comes before 'yne' alphabetically

Terminal 'e’ is dropped if it is followed by the suffix beginning with alphabets a, i, o, u or y.



Hence, correct IUPAC name is Hex-1-en-5-yne

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