Question

IUPAC name of the compound is: $C{H}_3-\underset{Cl}{\underset{|}{C}}=\underset{C{H}_3}{\underset{|}{C}}-\underset{C_2{H}_5}{\underset{|}{C}H}-C{H}_2-C\equiv CH$

• A. $6$-Chloro-$4$-ethyl-$5$-methyl hept-$5$-en-$1$-yne
• B. $6$-Chloro-$4$-ethyl-$5$-methyl hept-$1$-yn-Hne
• C. $2$-Chloro-$4$-ethyl-$3$-methyl hept-$2$-en-$6$-yne
• D. $2$-Chloro-$4$-ethyl-$3$-methyl hept-$4,3$-yn-$2$-ene

Answer 1

The correct option is C $2$-Chloro-$4$-ethyl-$3$-methyl hept-$2$-en-$6$-yne

C. 2-Chloro-4-ethyl-3-methylhept-2-en-6-yne
By the functional group priority alkene and chloro group gets priority and by lowest sum rule positions are given to $7$ carbon atoms. The naming starts from alphabetical order of chloro group then ethyl group,substituent and then positions of double and triple bond.