IUPAC name of this compound is:

$B r - C H_{2} - C H = C H - C H_{3}$

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Solution

The given compound is-
$B r - C H_{2} - C H = C H - C H_{3}$
As the given compound contains one bromide group $(- B r)$ at $C - 1$ while a double bond at $C - 2$ . Hence the IUPAC name of the compound is $1$ -Bromobut- $2$ -ene.

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The IUPAC name of the compound CH₃−CH₂−CH=CH−CH₂−CH₃ is .

C H_{3} - C H_{2} - O H | C H - C H_{2} - C H_{2} - C | H C H_{3} - C H_{2} - C H_{3}

The IUPAC name of the following compound is?

$C H_{3} - C H_{2} - C H_{2} - C | H C H_{3} - C H_{2} - C H_{3} | C H - C H_{3}$

I U P A C

{C H}_{3} - C | B r = C H - C H_{2} O H

{C H}_{3} - C H_{2} - C H = C H - \circ ∥ C - H O H

H_{3} C - C H_{2} - C H_{3} | C = C H - C | H C_{2} H_{5} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{3}

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