Question 3 (iv)
Are the following pair of linear equations consistent? Justify your answer
x + 3y = 11 and 2(2x + 6y) = 22

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Solution

x + 3y = 11 and 2x + 6y = 11
$a_{1} = 1, b_{1} = 3, c_{1} = - 11 a_{2} = 2, b_{2} = 6, c_{2} = - 11 n o w, \frac{a_{1}}{a_{2}} = \frac{1}{2}, \frac{b_{1}}{b_{2}} = \frac{3}{6} = \frac{1}{2}, \frac{c_{1}}{c_{2}} = \frac{- 11}{- 11} = 1 \frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$
Hence, the pair of linear equation have no solution i.e., inconsistent.

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Question 3 (iv)
Are the following pair of linear equations consistent? Justify your answer
x + 3y = 11 and 2(2x + 6y) = 22

Question 3 (iv)
Are the following pair of linear equations consistent? Justify your answer
x + 3y = 11 and 2(2x + 6y) = 22

Q. The following pair of linear equations consistent. State true and false:

x + 3 y = 11

;

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Question 3 (ii)
Are the following pair of linear equations consistent? Justify your answer.
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Question 3 (iii)
Are the following pair of linear equations consistent? Justify your answer
2a + by = a and 4a + 2by -2a = 0; a, b $\neq$ 0

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Question 3 (iv) Are the following pair of linear equations consistent? Justify your answer x + 3y = 11 and 2(2x + 6y) = 22

x + 3y = 11 and 2x + 6y = 11 a1=1, b1=3, c1=−11a2=2, b2=6, c2=−11now, a1a2=12, b1b2=36=12,c1c2=−11−11=1a1a2=b1b2≠c1c2 Hence, the pair of linear equation have no solution i.e., inconsistent.

Question 3 (iv)
Are the following pair of linear equations consistent? Justify your answer
x + 3y = 11 and 2(2x + 6y) = 22