Question 177iv Find it -6-7x-7-1

We have, ( 6/7)^x 7 = 1 Using law of exponents, x^0 = 1 [∵ a is non zero integer] Then, ( 6/7)^x 7 = 1 It is possible only, if x = 7. So, ( 6/7)^7 ...

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Standard X

Mathematics

Degree of a Polynomial

Question 177i...

Question

Question 177(iv)

Find it
${(\frac{- 6}{7})}^{x - 7} = 1$

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Solution

We have, ${(- \frac{6}{7})}^{x - 7} = 1$
Using law of exponents, $x^{0} = 1$ [ $∵$ a is non-zero integer]
Then, ${(- \frac{6}{7})}^{x - 7} = 1$
It is possible only, if x = 7.
So, ${(- \frac{6}{7})}^{7 - 7} = 1$
$\Rightarrow {(- \frac{6}{7})}^{0} = 1$
Hence, x = 7

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Question 177(iv)

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${(\frac{- 6}{7})}^{x - 7} = 1$

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Find x.
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Question 177(i)

Find x.
$- {(\frac{1}{7})}^{- 5} \div - {(\frac{1}{7})}^{- 7} = (- 7)^{x}$

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Question 177(iv) Find it (−67)x−7=1

We have, (−67)x−7=1 Using law of exponents, x0=1 [∵ a is non-zero integer] Then, (−67)x−7=1 It is possible only, if x = 7. So, (−67)7−7=1 ⇒(−67)0=1 Hence, x = 7

Question 177(iv)

Find it
${(\frac{- 6}{7})}^{x - 7} = 1$

We have, ${(- \frac{6}{7})}^{x - 7} = 1$
Using law of exponents, $x^{0} = 1$ [ $∵$ a is non-zero integer]
Then, ${(- \frac{6}{7})}^{x - 7} = 1$
It is possible only, if x = 7.
So, ${(- \frac{6}{7})}^{7 - 7} = 1$
$\Rightarrow {(- \frac{6}{7})}^{0} = 1$
Hence, x = 7