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Inter Conversion between Standard and Normal Forms

iv Find the v...

Question

Question 1(iv)
Find the value of:
(iv) $5^{4}$

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Solution

(iv) $5^{4}$

Here '5' is called the base and ‘4’ the exponent.

$5^{4} = 5 \times 5 \times 5 \times 5 = 625$

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Similar questions

Question 1(iv)
Find the common factors of the terms
$2 x, 3 x^{2}, 4$

4 p^{3}, - 3 p

Find the value of:
(i) ${(\frac{5}{8})}^{- 1}$
(ii) ${(\frac{- 4}{9})}^{- 1}$
(iii) $(- 7)^{- 1}$
(iv) ${(\frac{1}{- 3})}^{- 1}$

{(\frac{1}{4})}^{- 4} \times {(\frac{1}{4})}^{- 8} = {(\frac{1}{4})}^{- 4 x}

{(\frac{- 1}{2})}^{- 19} \times {(\frac{- 1}{2})}^{8} = {(\frac{- 1}{2})}^{- 2 x + 1}

{(\frac{3}{2})}^{- 3} \times {(\frac{3}{2})}^{5} = {(\frac{3}{2})}^{2 x + 1}

{(\frac{2}{5})}^{- 3} \times {(\frac{2}{5})}^{15} = {(\frac{2}{5})}^{2 + 3 x}

{(\frac{5}{4})}^{- x} \div {(\frac{5}{4})}^{- 4} = {(\frac{5}{4})}^{5}

{(\frac{8}{3})}^{2 x + 1} \times {(\frac{8}{3})}^{5} = {(\frac{8}{3})}^{x + 2}

2 x^{2} - x + \frac{1}{8} = 0

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