Question 83 (iv)
Multiply the following :
−5a2bc,11ab,13abc2
We have, −5a2bc,11ab and 13abc2 ∴−5a2bc×11ab×13abc2=(−5×11×13)a2bc×ab×abc2=−715a4b3c3
−7pq2r3,−13p3q2r
Question 83 (ii)
3x2y2z2,17xyz
Question 83 (iii)
15xy2,17yz2