Question 111(iv)
Use the distributivity of multiplication of rational numbers over addition to simplify.
$\frac{3}{4} \times [\frac{8}{9} - 40]$

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Solution

Given, $\frac{3}{4} \times (\frac{8}{9} - 40) = \frac{3}{4} \times \frac{8}{9} + (\frac{3}{4}) \times (- 40)$
[by using distributive property over addition]
$= \frac{2}{3} - 30 = \frac{2 - 90}{3} = \frac{- 88}{3}$

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Similar questions

\frac{2}{7} \times [\frac{7}{16} - \frac{21}{4}]

\frac{3}{5} \times [\frac{35}{24} + \frac{10}{1}]

Use the distributivity of multiplication of rational numbers over their addition to simplify:

(i) $\frac{3}{5} \times (\frac{35}{24} + \frac{10}{1})$

(ii) $\frac{- 5}{4} \times (\frac{8}{5} + \frac{16}{5})$

(iii) $\frac{2}{7} \times (\frac{7}{16} - \frac{21}{4})$

(iv) $\frac{3}{4} \times (\frac{8}{9} - 40)$

\frac{3}{5} \times (\frac{35}{24} + \frac{10}{1})

\frac{- 5}{4} \times (\frac{8}{5} + \frac{16}{5})

\frac{2}{7} \times (\frac{7}{16} - \frac{21}{4})

\frac{3}{4} \times (\frac{8}{9} - 40)

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