Question 5 (iv)

When a = 0, b = -1, find the value of the given expression:
$a^{2} + a b + 2$

Open in App

Solution

$a^{2} + a b + 2 = (0)^{2} + (0) (- 1) + 2$ [Putting a = 0, b = -1]

= 0 + 0 + 2 = 2

Suggest Corrections

Similar questions

Question 5 (iii)

When a = 0, b = -1, find the value of the given expression:
$2 a^{2} b + 2 a b^{2} + a b$

Question 5 (ii)

When a = 0, b = -1, find the value of the given expression:
$2 a^{2} + b^{2} + 1$

Question 5 (i)

When a = 0, b = -1, find the value of the given expression:
2a + 2b

When a = 0, b = − 1, find the value of the given expressions:

(i) 2a + 2b (ii) 2a²+ b² + 1

(iii) 2a²b + 2ab² + ab (iv) a² + ab + 2

Question 178(iv)

If a = -1, b = 2, then find the value of the following.
$a^{b} \div b^{a}$

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program