Question 85 (ix)
Expand the following, using suitable identities.
(2x3−23)(2x3+2a3)
We have, [using the identity, (x+a)(x+b)=x2+(a+b)x+ab] =4x29+2a−23×23x−49a=4x29+49(a−1)x−49a
Question 85 (iv)
(23x−32y)2
Question 85 (xi)
(2a3+b3)(2a3−b3)
Question 85 (vi)
(x+3)(x+7)
Question 85 (vii)
(2x+9)(2x−7)