Jack and Jill expanded ${(x - 7)}^{2}$ . Jack’s answer is ( $x^{2} - 49)$ and Jill’s answer is $x^{2} - 14 x + 49$ . Choose the right option.

Jack’s answer is correct.

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Jill’s answer is correct.

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Both answers are correct.

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Both answers are incorrect.

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Solution

The correct option is B Jill’s answer is correct.
Using the identity,  ${(a - b)}^{2}$ =  $a^{2} - 2 a b + b^{2}$ ,
${(x - 7)}^{2}$ can be expanded as:

 ${(x - 7)}^{2}$ =  $x^{2} - 14 x + 49$

So, Jill’s answer is correct.

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Similar questions

Q. Simplify:

x^{2} + 14 x + 49

Q. Factorise :

x^{2} + 14 x + 49

Q. Solve

x^{2} + 49 + 14 x

Q. Divide the following and write your answer in lowest terms:

\frac{x^{2} - 36}{x^{2} - 49} \div \frac{x + 6}{x + 7}

Let f(x) = $x^{2}$ -1, 0 0<x<2 and 2x+3, 2 $\leq$ x<3, The quadratic equation whose roots are ${lim}_{x \to 2^{-}} f (x), a n d {lim}_{x \to 2^{+}} f (x)$

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Jack and Jill expanded (x−7)2. Jack’s answer is (x2−49) and Jill’s answer is x2−14x+49. Choose the right option.

Jack and Jill expanded ${(x - 7)}^{2}$ . Jack’s answer is ( $x^{2} - 49)$ and Jill’s answer is $x^{2} - 14 x + 49$ . Choose the right option.