Question

Jack and Ruth went to a math amusement park. It was compulsory there to solve given math problem to enter into the park.
Simplify: $\sqrt{98}+\sqrt{50}-\sqrt{16}$

• A. $12\sqrt{2}-4$
• B. $12\sqrt{2}+4$
• C. $\sqrt{2}-4$

Answer 1

The correct option is A $12\sqrt{2}-4$

Given: $\sqrt{98}+\sqrt{50}-\sqrt{16}$

$\sqrt{98}=\sqrt{2\times 7\times 7}=7\sqrt{2}$

$\sqrt{50}=\sqrt{2\times 5\times 5}=5\sqrt{2}$

$\sqrt{16}=\sqrt{4\times 4}=4$

Hence, $\sqrt{98}+\sqrt{50}-\sqrt{16}=7\sqrt{2}+5\sqrt{2}-4=12\sqrt{2}-4$