Question

Jack has arranged bricks with numbers on them so that there are five bricks in Row I, four bricks in Row II, three bricks in Row III, two bricks in Row IV, and only one brick in Row V.
Find the pattern and identify the number that will be there on the brick in Row V.
10 20 36 864 11

• A. 600
• B. 2128
• C. 1118
• D. 1128

Answer 1

The correct option is D 1128

Number of bricks in Row I = 5
Number of bricks in Row II = 4
Number of bricks in Row III = 3
Number of bricks in Row IV = 2
Number of bricks in Row V = 1

Row II :
$\text{Here,}10\times 2=20$
Similarly,
$2\times 8=16$
$8\times 1=8$
$1\times 3=3$
Thus, the numbers in Row II are the product of two numbers from Row I.


Row III:
Here, 20 + 16 = 36
Similarly,
16 + 8 = 24
8 + 3 = 11
Thus, the numbers in Row III are the sum of the two numbers from Row II.


Row IV:
$\text{Here,}36\times 24=864$
$\text{Similarly,}24\times 11=264$
Thus, the numbers in Row IV are the product of two numbers from Row III.


From the pattern, we can say that the number on the brick in Row V will be the sum of the numbers in Row IV.

Thus, 864 + 264 = 1128.