Jacob has a habit of oversleeping in the morning and when he oversleeps, he misses his breakfast. The probability of him oversleeping is 0.4. What is the probability that he eats his breakfast?
A
0.4
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B
0.3
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C
0.5
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D
0.6
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Solution
The correct option is D0.6
Jacob can eat breakfast if he does not oversleep in the morning. So, to calculate the probability of eating breakfast, we need to calculate the probability of not oversleeping by Jacob.
As per the question, P(oversleeping)=0.4
And, we know P(not oversleeping)=1−P(oversleeping) ⇒P(¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯oversleeping)=1−0.4 ⇒P(¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯oversleeping)=0.6
∴ The probability that Jacob eats the breakfast is 0.6.