Question

James and Robert are friends who stay in San Jose and Jacksonville, respectively. They planned to meet at Dallas. They started their journey towards Dallas at 80 mph and 95 mph, respectively. Coincidently, they reached Dallas at the same time and one of them travelled 180 miles more than the other. Find the distance between San Jose and Jacksonville.

• A. 2,400 miles
• B. 2,100 miles
• C. 1,800 miles
• D. 2,700 miles

Answer 1

The correct option is B 2,100 miles

Both of them reach Dallas in the same time. Hence, Robert travels at 95 mph since he covers 180 miles more.

Let the distance between San Jose and Dallas = x miles
Distance between Jacksonville and San Jose = (x + 180) miles

Time taken by James = $\frac{x}{80}$
Time taken by Robert = $\frac{x+180}{95}$

The time taken is equal for both. So,
$\frac{x}{80}=\frac{x+180}{95}$

$x=960miles$

Distance between San Jose and Jacksonville $=x+x+180=2,100miles$