Question

Jar A contains 3 gallons of juice, whereas Jar B contains 21 quarts of juice. The juice in jars A and B is poured into Jar C. If one-third of the juice from Jar C is taken out, calculate the amount of juice remaining in Jar C.
(Hint: 1 gallon = 4 quarts)

• A. 5.3 gal
• B. 5 gal
• C. 5.1 gal
• D. 5.5 gal

Answer 1

The correct option is D 5.5 gal

Amount of juice in Jar A = 3 gal

Amount of juice in Jar B = 21 qt
1 gal = 4 qt
$\Rightarrow 1qt=\frac{1}{4}gal$
$\Rightarrow 21qt=\frac{1}{4}\times 21$
= 5.25 gal

Hence, amount of juice in Jar B = 5.25 gal

According to the question,
Amount of juice in Jar C = amount of juice in Jar A + amount of juice in Jar B
= 3 + 5.25
= 8.25 gal
Amount of juice taken out from Jar $C=\frac{1}{3}$ of the amount of juice in Jar C
Remaining amount of juice in Jar $C=(1-\frac{1}{3})$ of the amount of juice in Jar C

$=\frac{2}{3}$of the amount of juice in Jar C
$=\frac{2}{3}\times 8.25=5.5$ gal
Hence, the amount of juice remaining in Jar C is 5.5 gal.