wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Jar A contains 3 litres of juice, whereas Jar B contains 5 litres 250 ml of juice.
In jar C, both juices are combined, and one-third of the juice is withdrawn from the jar C. Calculate the amount of juice remaining in jar C.

A
5 l
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5.1 l
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5.5 ml
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5.5 l
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 5.5 l
Volume of juice in jar A =3l
Volume of juice in jar B =5l 250ml
Convert ml into liter
We know,
1l=1000ml
250ml=2501000=0.25 l
Now,
5l 250ml=5l+0.25l=5.25l
According to question,
Amount of juice in jar C initially = Amount of juice in jar A + Amount of juice in jar B
=3l+5.25l
=8.25l

Amount of juice taken out from jar C =13 of the amount of juice in jar C
Amount of juice remaining in jar C =(113) of the amount of juice in jar C
=23 of the amount juice in jar C
=23×8.25=5.5l ( juice in jar C = 8.25l)
Hence, amount of juice remaining in jar C is 5.5 l.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conversion of Metric Units
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon