Question

Jax adds 23 chocolates to Jane’s box. Jane already had a few chocolates in her box. Now, she has a total of 74 chocolates.
(i) How do we represent this problem?
(ii) How many chocolates did Jane have before?

• A. (i) ___ + 23 = 74, (ii) 61
• B. (i) ___ + 23 + 3 = 74 + 4, (ii) 55
• C. (i) 23 + 20 + ___ = 70 + 4, (ii) 65
• D. (i) __+__ + 20 + 3 = 70 + 4, (ii) 51

Answer 1

The correct option is D (i) __+__ + 20 + 3 = 70 + 4, (ii) 51

Say:
We know that Jax adds 23 chocolates to Jane’s box. Jane already had a few chocolates in her box. Now, she has a total of 74 chocolates.

Steps:

• The equation can be: ____ + 23 = 74
• To find the solution, we can:
• Count forward from 23 to 74 (addition)
• Count back from 74 to 23 (subtraction)
• For both, let us decompose the numbers to make our calculation easier.
• ____ + 20 + 3 = 70 + 4
• Let us count forward by grouping Tens together and Ones together.
• From 20 to 70, we will count: 50
• From 3 to 4, we will count: 1
• Therefore, we have to count 50 + 1 = 51.
• Hence, option B is correct.