Question

Jax has 25 toys. The number of toys Jane has is more than those with Jax. Together, they have more than 60 toys. How many toys does Jane have?

• A. 24
• B. 33
• C. 29
• D. 38

Answer 1

The correct option is D 38

Say:
Let us look at each option to identify the number of toys Jane has. We know that Jax has 25 toys and the total number of toys should be more than 60.

Steps:

• We break down 25 into 2 Tens and 5 Ones, represented by 2 rods and 5 units, and add each option to this to find the option that adds up to more than 60.
• Option A: 29 is broken down into 2 Tens and 9 Ones, represented by 2 rods and 9 units.
• Add the Ones, i.e., 5 + 9 = 14. Then, add the Tens, i.e., 20 + 20 = 40. Further, regroup and add the Tens and Ones, i.e., 40 + 14 = 54, represented by 5 rods and 4 units.
• As 54 is less than 60, so Option A is incorrect.
• Option B: 33 is broken down into 3 Tens and 3 Ones, represented by 3 rods and 3 units.
• Add the Ones, i.e., 5 + 3 = 8. Then, add the Tens, i.e., 20 + 30 = 50. Further, add the Tens and Ones, i.e., 50 + 8 = 58, represented by 5 rods and 9 units. As 58 is less than 60, so Option B is also incorrect.
• Option C: 24 is broken down into 2 Tens and 4 Ones, represented by 2 rods and 4 units.
• Add the Ones, i.e., 5 + 4 = 9. Then, add the Tens, i.e., 20 + 20 = 40. Further, add the Tens and Ones, i.e., 40 + 9 = 49, represented by 4 rods and 9 units.
• As 49 is less than 60, Option C is also incorrect.
• Options D: 38 is broken down into 3 Tens and 8 Ones, represented by 3 rods and 8 units.
• Add the Ones, i.e., 5 + 8 = 13. Then, add the Tens, i.e., 20 + 30 = 50. Further, regroup and add the Tens and Ones, i.e., 50 + 13 = 63, represented by 6 rods and 3 units.
• As 63 is more than 60, hence option D is the answer.

WB: If required, use the whiteboard to break down the numbers and draw rods and units to solve the equation as shown.