Jayanti takes shortest route to her home by walking diagonally across a rectangular park- The park measures 60 meters- 80 meters- How much shorter is the route across the park than the route around its edges-

Let ABCD in right angled.Triangle ABC is right angled. ⇒ (AC)^2=(80)^2+(60)^2 ⇒ AC=√(6400+3600) ⇒ AC=√(10000) ⇒ AC=100 Hence, len ...

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Standard VII

Mathematics

Circumference of a Circle

Jayanti takes...

Question

Jayanti takes shortest route to her home by walking diagonally across a rectangular park. The park measures $60 m e t e r s \times 80 m e t e r s$ . How much shorter is the route across the park than the route around its edges?

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Solution

Let $A B C D$ in right-angled.
Triangle $A B C$ is right-angled.
$\Rightarrow (A C)^{2} = (80)^{2} + (60)^{2}$
$\Rightarrow A C = \sqrt{6400 + 3600}$
$\Rightarrow A C = \sqrt{10000}$
$\Rightarrow A C = 100$
Hence, length of the route across the park $= 100 m$
Length of route around the edges $= (80 + 60) = 140 k m$
Therefore, the shorter route is
$\Rightarrow 140 m - 100 m = 40 m$

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Jayanti takes shortest route to her home by walking diagonally across a rectangular park. The park measures 60meters×80meters. How much shorter is the route across the park than the route around its edges?

Let ABCD in right-angled.Triangle ABC is right-angled.⇒(AC)2=(80)2+(60)2⇒AC=√6400+3600⇒AC=√10000⇒AC=100Hence, length of the route across the park =100mLength of route around the edges =(80+60)=140km Therefore, the shorter route is ⇒140m−100m=40m

Jayanti takes shortest route to her home by walking diagonally across a rectangular park. The park measures $60 m e t e r s \times 80 m e t e r s$ . How much shorter is the route across the park than the route around its edges?