Question

Jennifer, Mona and Robert went out for dinner. Jennifer paid 1/3, Mona paid 4/12, and Robert paid 6/18 of the bill amount. Who paid more?

• A. Jennifer
• B. Mona
• C. Robert
• D. All paid the same amount

Answer 1

The correct option is D All paid the same amount

Jennifer paid = $\frac{1}{3}$ of the total bill amount.

If we multiply the denominator and the numerator of $\frac{1}{3}$ by 4 we will get $\frac{4}{12}$

i.e. $\frac{1\times 4}{3\times 4}=\frac{4}{12}$

Similary, if we multiply the denominator and the numerator of $\frac{1}{3}$ by 6 we will get $\frac{6}{18}$

i.e. $\frac{1\times 6}{3\times 6}=\frac{6}{18}$

Thus, $\frac{1}{3},\frac{4}{12}$ and $\frac{6}{18}$ are equivalent fractions.

So, all of them paid the same amount.