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Question

Jenny is 9 years younger than Sammie.

Five years ago Sammie was 4 times older than Jennie.

How old is each now?


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Solution

Step-1: Form an algebraic equation:

Given that Jenny is 9 years younger than Sammie.

Let present age of Sammie be x then age of Jennie will be x-9.

Also given that 5 years ago Sammie was 4years older than Jennie.

Age of Sammie 5 years ago will be x-5 .

Age of Jenny will be x-9-5=x-14.

5 years ago Sammie was 4 times older than Jennie.

Therefore , x-5=4×x-14 is the required equation.

Step 2.Solve the equation.

x-5=4×x-14x-5=4x-56x-4x=-56+5-3x=-51x=-51-3x=17

The present age of Sammie is 17 years.

Substitute the value of x in Jennie's age that is x-9.

17-9=8

Hence, Present age of Jammie is 8 years.


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