Jim drops a ball from the top of a building whose height is 20 m. What will be the final velocity of the ball just before it strikes the ground. $g = 10 m / s^{2}$

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Solution

$v^{2} = u^{2} + 2 as Therefore, v = 20 m / s$

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Jim drops a ball from the top of a building whose height is 20 m. What will be the final velocity of the ball just before it strikes the ground. g=10m/s2

v2=u2+2asTherefore, v=20m/s

Jim drops a ball from the top of a building whose height is 20 m. What will be the final velocity of the ball just before it strikes the ground. $g = 10 m / s^{2}$

$v^{2} = u^{2} + 2 as Therefore, v = 20 m / s$