Jim went bird watching and photographed each bird he saw in 9 different ways. How many unique birds did Jim witness if he shot a total of 45 photos.

5

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7

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9

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Solution

The correct option is A $5$
Total number of pictures took by jim $= 45$
Number of pictures of each bird $= 9$

Number of birds seen by Jim = $\frac{total number of pictures}{number of pictures of each bird} = \frac{45}{9}$ .

$45 \div 9 = 5 R 0$ Quoteint = 5
Thererfore, Jim saw 5 unique birds

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Jim went bird watching and photographed each bird he saw in 9 different ways. How many unique birds did Jim witness if he shot a total of 45 photos.

The correct option is A 5Total number of pictures took by jim =45 Number of pictures of each bird =9 Number of birds seen by Jim = total number of picturesnumber of pictures of each bird=459. 45÷9=5 R 0Quoteint = 5 Thererfore, Jim saw 5 unique birds

The correct option is A $5$
Total number of pictures took by jim $= 45$
Number of pictures of each bird $= 9$

Number of birds seen by Jim = $\frac{total number of pictures}{number of pictures of each bird} = \frac{45}{9}$ .

$45 \div 9 = 5 R 0$ Quoteint = 5
Thererfore, Jim saw 5 unique birds