Joe drives 120 km at 60 kmph, and then he drives the next 120 km at 40 kmph. What is his average speed for the entire trip in kmph?

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Solution

The correct option is B
48

Time taken for first part of the journey, $t_{1} = \frac{120}{60} = 2 h$

Time taken for last part of the journey, $t_{2} = \frac{120}{40} = 3 h$

Total time taken, $t = t_{1} + t_{2} = 2 + 3 = 5 h$

Total distance covered $= 120 + 120 = 240 k m$

So, average speed $= \frac{T o t a l D i s t a n c e}{T o t a l T i m e} = \frac{240}{5} = 48 k m p h$

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Joe drives 120 km at 60 kmph, and then he drives the next 120 km at 40 kmph. What is his average speed for the entire trip in kmph?

The correct option is B 48 Time taken for first part of the journey, t1=12060=2 h Time taken for last part of the journey, t2=12040=3 h Total time taken, t=t1+t2=2+3=5 h Total distance covered =120+120=240 km So, average speed =Total DistanceTotal Time=2405=48 kmph