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Question

Joe has 'j' peanuts. Sonia has 3 fewer peanuts than Joe. Mack has 5 more than Joe. Match the peanuts each has.

A
j
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B
j3
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C
j+5
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Solution

Concept Involved:–––––––––––––––––––
'Fewer' suggests that we need to subtract that amount from the reference amount.

'More' suggests that we need to add that amount into the reference amount.

Method:––––––––

Joe has 'j' peanuts.

Sonia has 3 fewer peanuts than Joe. Therefore, Sonia has 'j - 3' peanuts.

Mack has 5 more peanuts than Joe. Hence, Mack has 'j + 5' peanuts.

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