Question

John and Marcus took two different exams. John scored 36 out of 40, and Marcus scored 42 out of 70. Who earned the higher grade, and what percentage did he score?

• A. Marcus, 90%
• B. John, 60%
• C. John, 90%
• D. Marcus, 60%

Answer 1

The correct option is C

John, 90%

(b)

Step 1: Convert the grades into fractions.

Jhon's marks=$\frac{36}{40}$
Marcus's marks =$\frac{42}{70}$

Step 2:Convert the fractions into percentage.

$\frac{36}{40}=\frac{x}{100}$

$x=\frac{100\times 36}{40}$

$x=\frac{10\times 10\times 9\times 4}{4\times 10}$

$x=90$

$\Rightarrow \frac{36}{40}=\frac{90}{100}$

=90%

Jhon's grade =90%

Now, repeat the above process to get y for the equation$\frac{42}{70}=\frac{y}{100}$

$\frac{42}{70}=\frac{y}{100}$

$y=\frac{100\times 42}{70}$

$y=60$

$\frac{42}{70}=\frac{60}{100}$

=60 %.

Marcus's grade =60%.

Step 3: Compare the grades to see who got a higher grade.

Jhon's grade = 90%
Marcus's grade =60%

So,
Jhon's grade is higher than Marcus's grade and he got 90%.