Question

John has cut a piece of paper into an obtuse triangle. The area of an obtuse angle triangle is $48{\text{ft}}^2$ and the base of a triangle is 12 ft. The height of the triangular piece of paper is__

• A. 2 ft
• B. 6 ft
• C. 10 ft
• D. 8 ft

Answer 1

The correct option is D 8 ft

Given,
Area of a triangle $=48{\text{ft}}^2$
Base of a triangle$=BC=12$ ft
Let height of a triangle $=h$
As we know,
$\text{Area of}△ABC=\frac{1}{2}\times \text{Base}\times \text{Height}$

$48=\frac{1}{2}\times 12\times h$

$h=\frac{48\times 2}{12}=\frac{96}{12}=8ft$

Hence, the height of a triangular piece of paper is 8 ft.

Option (d) is correct.