Joseph jogs from 1 and 8 to another and B of a straight 300m road in 2 minutes 50 seconds and then turns around and job 100m back to. See in another 1 minute what are Joseph's average speed and velocity in jogging from a to b and from a to c
Joseph jogs from 1 and 8 to another and B of a straight 300m road in 2 minutes 50 seconds and then turns around and job 100m back to. See in another 1 minute what are Joseph's average speed and velocity in jogging from a to b and from a to c
we know that average speed is simply defined as the rate at which an object covers a certain distance. Mathematically, it given as
total distance travelled by object / total time taken by object to do so
and average velocity is simple defined as the ratio of total displacement acquired by the body and the time taken to do so.
(1)
average speed from A to B
In this case the total distance travelled by the object will be AB = 300m
total time taken by the body to go form A to C = time from A to B = 2min50s = 170s
so,
average speed = 300/170 = 1.764 m/s
similarly, average velocity from A to B
here the net displacement acquired will be = AB = 300m
total time taken will be the same as previously = 170s
thus,
average velocity = 300/170 = 1.764 m/s
(2)
average speed from A to C
In this case the total distance travelled by the object will be AC = AB + BC = 300m + 100m = 400m
total time taken by the body to go form A to C = time from A to B + time from B to C = 2min50s + 1min = 3min50s = 230s
so,
average speed = 400/230 = 1.739 m/s
similarly, average velocity from A to C
here the net displacement acquired will be AC = AB - BC = 300m - 100m = 200m
total time taken will be the same as previously = 230s
thus,
average velocity = 200/230 = 0.869 m/s
we know that average speed is simply defined as the rate at which an object covers a certain distance. Mathematically, it given as
total distance travelled by object / total time taken by object to do so
and average velocity is simple defined as the ratio of total displacement acquired by the body and the time taken to do so.
(1)
average speed from A to B
In this case the total distance travelled by the object will be AB = 300m
total time taken by the body to go form A to C = time from A to B = 2min50s = 170s
so,
average speed = 300/170 = 1.764 m/s
similarly, average velocity from A to B
here the net displacement acquired will be = AB = 300m
total time taken will be the same as previously = 170s
thus,
average velocity = 300/170 = 1.764 m/s
(2)
average speed from A to C
In this case the total distance travelled by the object will be AC = AB + BC = 300m + 100m = 400m
total time taken by the body to go form A to C = time from A to B + time from B to C = 2min50s + 1min = 3min50s = 230s
so,
average speed = 400/230 = 1.739 m/s
similarly, average velocity from A to C
here the net displacement acquired will be AC = AB - BC = 300m - 100m = 200m
total time taken will be the same as previously = 230s
thus,
average velocity = 200/230 = 0.869 m/s
