wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Joseph jogs from 1 and 8 to another and B of a straight 300m road in 2 minutes 50 seconds and then turns around and job 100m back to. See in another 1 minute what are Joseph's average speed and velocity in jogging from a to b and from a to c

Open in App
Solution

we know that average speed is simply defined as the rate at which an object covers a certain distance. Mathematically, it given as

total distance travelled by object / total time taken by object to do so

and average velocity is simple defined as the ratio of total displacement acquired by the body and the time taken to do so.

(1)

average speed from A to B

In this case the total distance travelled by the object will be AB = 300m

total time taken by the body to go form A to C = time from A to B = 2min50s = 170s

so,

average speed = 300/170 = 1.764 m/s

similarly, average velocity from A to B

here the net displacement acquired will be = AB = 300m

total time taken will be the same as previously = 170s

thus,

average velocity = 300/170 = 1.764 m/s

(2)

average speed from A to C

In this case the total distance travelled by the object will be AC = AB + BC = 300m + 100m = 400m

total time taken by the body to go form A to C = time from A to B + time from B to C = 2min50s + 1min = 3min50s = 230s

so,

average speed = 400/230 = 1.739 m/s

similarly, average velocity from A to C

here the net displacement acquired will be AC = AB - BC = 300m - 100m = 200m

total time taken will be the same as previously = 230s

thus,

average velocity = 200/230 = 0.869 m/s


flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Visualised
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon