Joseph jogs from one end A to the other end B of the straight 300 m road in 2 minutes 50 seconds and then turns around and jogs 100 m back to point C in another 1 minute. Joseph's average speeds and velocities in jogging, between points A and B, respectively, will be

1.76 m s^{- 1}, 1.76 m s^{- 1}

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0.869 m s^{- 1}, 0.869 m s^{- 1}

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1.76 m s^{- 1}, 0.869 m s^{- 1}

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0.869 m s^{- 1}, 1.76 m s^{- 1}

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Solution

The correct option is D. $1.76 m s^{- 1}, 1.76 m s^{- 1}$
Between points A and B,
T = 2 minute 50 second = 170 sec.

Average speed= $\frac{Total distance}{Time}$
Average speed= $\frac{300}{170} = 1.76 m s^{- 1}$

Average velocity= $\frac{Total displacement}{Time}$
Average velocity= $\frac{300}{170} = 1.76 m s^{- 1}$

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Joseph jogs from one end A to the other end B of the straight 300 m road in 2 minutes 50 seconds and then turns around and jogs 100 m back to point C in another 1 minute. Joseph's average speeds and velocities in jogging, between points A and B, respectively, will be

The correct option is D. 1.76 ms−1,1.76 ms−1Between points A and B,T = 2 minute 50 second = 170 sec.Average speed= Total distanceTimeAverage speed= 300170=1.76 ms−1Average velocity= Total displacementTimeAverage velocity= 300170=1.76 ms−1