Question

Josh built a rectangular cardboard box 18 cm high with a square base and a volume of $2178c{m}^3$. After that he realized that he did not need a box that large so, he chopped off the height of the box and its volume reduces to $1331c{m}^3$. Find the height of the new cubical box.

• A. 11 cm
• B. 13 cm
• C. 15 cm
• D. 18 cm

Answer 1

The correct option is A 11 cm

(Length $\times$ Breadth) $\times$ Height
= (Base area) $\times$ Height
Base area = $\left(\frac{2178}{18}\right)$
= $121c{m}^2$
Length $\times$ Length = $121c{m}^2$
Length = 11 cm
Now,
$1331c{m}^3$ = 11 cm $\times$ 11 cm $\times$ new height
New height = $\frac{1331c{m}^3}{(11cm\times 11cm)}$
= 11 cm.