Joshita has purchased $10$ articles. The $1$ st article cost Rs. $1$ , the $2$ nd, Rs. $2$ , the $3$ rd, Rs. $4$ , and the $4$ th, Rs. $8$ , and so on. How much did John pay for the $10$ articles?

1023

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2023

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3023

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4023

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Solution

The correct option is A $1023$
To find the sum of the first $S_{n}$ terms of a geometric sequence use the formula,
$a = 1, r = 2, n = 10$

$S_{n} = \frac{a_{1} (1 - r^{n})}{1 - r}$
$S_{10} = \frac{1 (1 - 2^{10})}{1 - 2}$

$S_{10} = \frac{- 1023}{- 1}$

$S_{10} = 1023$

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Similar questions

John sold an article to Peter at 20% profit and Peter sold it to Mohan at 5% loss. If Mohan paid Rs.912 for the article; find how much did John pay for it ?

Q. Reena bought the following articles from a general store:
(i) 1 tie costing Rs 250 with ST @ 6%
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Solve the following problems:

If 3 articles can be purchased for Rs. 15. How many articles can be purchased for Rs. 75?

x

articles are bought at

R s . (x - 8)

each and

(x - 2)

some other articles are bought at

R s . (x - 3)

each. If the total cost of all these articles is

R s . 76

.How many articles of first Kind were bought?

Q. A man sells three articles. First article for

R s 24, 000

20 %

profit, second article for

R s 18, 900

125 %

profit and the third for

R s 14, 850.

If on the whole, he gains

3 \frac{1}{8} %,

find the cost price of the third article.

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Joshita has purchased 10 articles. The 1st article cost Rs. 1, the 2nd, Rs. 2, the 3rd, Rs. 4, and the 4th, Rs.8, and so on. How much did John pay for the 10 articles?

The correct option is A 1023To find the sum of the first Sn terms of a geometric sequence use the formula,a=1,r=2,n=10Sn=a1(1−rn)1−rS10=1(1−210)1−2S10=−1023−1S10=1023

Joshita has purchased $10$ articles. The $1$ st article cost Rs. $1$ , the $2$ nd, Rs. $2$ , the $3$ rd, Rs. $4$ , and the $4$ th, Rs. $8$ , and so on. How much did John pay for the $10$ articles?

The correct option is A $1023$
To find the sum of the first $S_{n}$ terms of a geometric sequence use the formula,
$a = 1, r = 2, n = 10$

$S_{n} = \frac{a_{1} (1 - r^{n})}{1 - r}$
$S_{10} = \frac{1 (1 - 2^{10})}{1 - 2}$

$S_{10} = \frac{- 1023}{- 1}$

$S_{10} = 1023$