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B
Momentum
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C
Angular momentum
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D
Power
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Solution
The correct option is C Angular momentum Joule is a unit of energy and second is the unit of time.
Thus, Joule×second has dimensions ML2T−2×T=ML2T−1 Now, energy cannot be the answer since energy has Joule as its unit and cannot be Joule-seconds. Momentum can't be the answer as momentum is force X time which has dimensions MLT−1 Angular momentum is given by cross product of linear momentum and radius vector thus it has dimensions MLT−1×L=ML2T−1, which is the correct answer. Finally, Power is force times velocity, so its dimensions are MLT−2×LT−1=ML2T−3