Julie has a square fence that enclosed her garden. She decided to expand her garden by making each side of the fence $10$ percent longer. After this expansion, the area of julie's graden will have increased by what percent?

20

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21

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22

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25

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Solution

The correct option is B $21$
Let $x$ be initial length of each side
Area $= x \times x = x^{2}$
Now since each length is increased by $10 %$
New length $= x + \frac{10}{100} x = \frac{11}{10} x$
New area $= \frac{11}{10} x \times \frac{11}{10} x = \frac{121}{100} x^{2}$
$N e w a r e a = x^{2} + \frac{21}{100} x^{2} =$ old area $+ 21 %$ of old area
$∴$ percent of increase is $21 %$

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Julie has a square fence that enclosed her garden. She decided to expand her garden by making each side of the fence 10 percent longer. After this expansion, the area of julie's graden will have increased by what percent?

The correct option is B 21Let x be initial length of each side Area =x×x=x2Now since each length is increased by 10%New length =x+10100x=1110xNew area =1110x×1110x=121100x2Newarea=x2+21100x2= old area +21% of old area∴ percent of increase is 21%

Julie has a square fence that enclosed her garden. She decided to expand her garden by making each side of the fence $10$ percent longer. After this expansion, the area of julie's graden will have increased by what percent?