Just as electricity is supplied at 220V in India, it is supplied 110 V in USA. If the resistance of 60W bulb for use in India is R, that of a 60W bulb for use in USA will be

R/4

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R/2

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Solution

The correct option is A
R/4

$R = \frac{v^{2}}{p} R \propto V^{2} R^{1} = R \propto {[\frac{v^{1}}{v}]}^{2} = [\frac{110 \times 110}{220 \times 220}] R^{1} = [\frac{R}{4}]$

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Just as electricity is supplied at 220V in India, it is supplied 110 V in USA. If the resistance of 60W bulb for use in India is R, that of a 60W bulb for use in USA will be

The correct option is A R/4 R=v2pR∝V2R1=R∝[v1v]2=[110×110220×220]R1=[R4]

The correct option is A
R/4

$R = \frac{v^{2}}{p} R \propto V^{2} R^{1} = R \propto {[\frac{v^{1}}{v}]}^{2} = [\frac{110 \times 110}{220 \times 220}] R^{1} = [\frac{R}{4}]$