Justify that $C_{3} H_{8}$ and ${CH}_{4}$ are the formulae of the homologous of ethane $(C_{2} H_{6})$ .

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Solution

Homologous series of compound lies in the same family and the molecular formula is different by one ${CH}_{2}$ unit.
Ethane $(C_{2} H_{6})$ is a saturated compound.
If a compound adds or subtract by one unit of ${CH}_{2}$ from that compound then it is a homologous compound.
The homologous of Ethane compound is by adding one unit of ${CH}_{2}$
$C_{2} H_{6} + {CH}_{2} \to C_{3} H_{8} Ethane propane (lower homologue) (higher homologue)$
The homologous of Ethane compound is by subtracting one unit of ${CH}_{2}$
$C_{2} H_{6} - {CH}_{2} \to {CH}_{4} Ethane Methane (higher homologue) (lower homologue)$
Hence, the two homologous of Ethane are $C_{3} H_{8}$ and ${CH}_{4}$ .

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Justify that C3H8 and CH4 are the formulae of the homologous of ethane (C2H6).

Justify that $C_{3} H_{8}$ and ${CH}_{4}$ are the formulae of the homologous of ethane $(C_{2} H_{6})$ .