Justify that the following reactions are redox reactions:

$2 K (s) + F_{2} (g) \to 2 K^{+} F^{-} (s)$

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Solution

The oxidation number of $K$ increases from $0$ to $+ 1$ and the oxidation number of $F_{2}$ decreases from $0$ to $- 1$ .

Hence, K is oxidized and $F_{2}$ is reduced.

Hence, it is a redox reaction.

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