Justify that the following reactions are redox reactions:

$4 B C l_{3} (g) + 3 L i A l H_{4} (g) \to 2 B_{2} H_{6} (g) + 3 L i C l (s) + 3 A l C l_{3} (s)$

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Solution

The oxidation number of $B$ decreases from $+ 3$ to $- 3$ . The oxidation number of hydrogen( $H$ ) increases from $- 1$ to $+ 1$ .

Hence, $B C l_{3}$ is reduced and $L i A l H_{4}$ is oxidized.

Hence, it is a redox reaction.

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(b) Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

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4 N C l 3 + 3 L i A l H 4 \to A + 3 L i C l + 3 A l C l_{3}

4 P C l_{3} + 3 L i A l H 4 \to B + 3 L i C l + 3 A l C l_{3}

4 A s C l_{3} + 3 L i A l H_{4} \to C + 3 L i C l + 3 A l C l_{3}

4 S b C l_{3} + 3 L i A l H_{4} \to D + 3 L i C l + 3 A l C l_{3}

4 N H_{3} (g) + 5 O_{2} (g) \to 4 N O (g) + 6 H_{2} (s)

4 N C l 3 + 3 L i A l H 4 \to A + 3 L i C l + 3 A l C l_{3}

4 P C l_{3} + 3 L i A l H 4 \to B + 3 L i C l + 3 A l C l_{3}

4 A s C l_{3} + 3 L i A l H_{4} \to C + 3 L i C l + 3 A l C l_{3}

4 S b C l_{3} + 3 L i A l H_{4} \to D + 3 L i C l + 3 A l C l_{3}

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