Question

$K_1$ and $K_2$ are equilibrium constant for reactions (1) & (2)

1. $N_2\left(g\right)+O_2\left(g\right)\rightleftharpoons 2NO\left(g\right)$

2. $NO\left(g\right)\rightleftharpoons \frac{1}{2}{N}_2\left(g\right)+\frac{1}{2}{O}_2\left(g\right)$

Then :

• A. $K_1={\left(\frac{1}{K_2}\right)}^2$
• B. $K_1=K_2^2$
• C. $K_1=\frac{1}{K_2}$
• D. $K_1=(K_2{)}^0$

Answer 1

The correct option is A $K_1={\left(\frac{1}{K_2}\right)}^2$

$N_2+O_2\rightleftharpoons 2NO...K_1$
$2NO\rightleftharpoons N_2+O_2...\frac{1}{K_1}$
$NO\rightleftharpoons \frac{1}{2}{N}_2+\frac{1}{2}{O}_2$

$K_2={\left(\frac{1}{K_1}\right)}^{\frac{1}{2}}$

$K_2={\left(\frac{1}{K_1}\right)}^{\frac{1}{2}}$

or ${K_2}^2=\frac{1}{K_1}$ or $K_1=\frac{1}{(K_2{)}^2}$