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Question

(k−1)C(k−1)+kC(k−1)+(k+1)C(k−1)+.......+(n+k−2)C(k−1) =?

A
(n+k)Ck
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B
(n+k+1)Ck
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C
(n+k)Ck1
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D
(n+k1)Ck
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Solution

The correct option is D (n+k1)Ck
k1Ck+kCk1–––––––––––––+....+n+k2Ck1
=k+1Ck+k+1Ck1––––––––––––––––+....+n+k2Ck1
=k+2Ck+...............+n+k2Ck1=n+k1Ck

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