K2Cr2O7 is obtained in the following steps: 2FeCrO4+2Na2CO3+O→Fe2O3+2Na2CrO4+2CO2 2Na2CrO4+H2SO4→Na2Cr2O7+H2O+Na2SO4 Na2Cr2O7+2KCl→K2Cr2O7+2NaCl To get 0.25 mol of K2Cr2O7, mol of 50% pure FeCrO4 required is:
A
1 mol
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B
0.50 mol
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C
0.25 mol
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D
0.125 mol
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Solution
The correct option is A1 mol K2Cr2O7 is obtained in the following steps: 2FeCrO4+2Na2CO3+O→Fe2O3+2Na2CrO4+2CO2 2Na2CrO4+H2SO4→Na2Cr2O7+H2O+Na2SO4 Na2Cr2O7+2KCl→K2Cr2O7+2NaCl 1mol K2Cr2O7 is obtained from 2 mol of FeCrO4. 0.25 mol K2Cr2O7 is obtained from =0.50 mol of FeCrO4 (100% pure)=1.00 mol (if 50% pure).