Question

$K_{3}Cr{\left(O_2\right)}_x$ has peroxy linkage with oxidation number of $Cr$ as $+5$. The value of $x$ is :

• A. $4$
• B. $3$
• C. $2$
• D. $6$

Answer 1

The correct option is A $4$

$K_{3}Cr{\left(O_2\right)}_x$ has $Cr{\left(O_2\right)}_x^{3-}$ ion.
Therefore, $+5-2x=-3$
or, $-2x=-8$
or, $x=4$.
It is $K_{3}Cr{\left(O_2\right)}_4$.