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Question

Ka for butyric acid is 2.0×105. Calculate pH and hydroxyl ion concentration in 0.2 M aqueous solution of sodium butyrate.

A
pH=5;[OH]=109M
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B
pH=5;[OH]=105M
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C
pH=9;[OH]=109M
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D
pH=9;[OH]=105M
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Solution

The correct option is D pH=9;[OH]=105M
NaBu + H2O NaOH + BuH
Initial conc. 1 0 0
Conc. after hydrolysis 1α α α
From hydrolysis of salt, we know,
[OH]=Cα=C.(KhC)=(Kh.C)
=[(KwKa).C],where,Kh=KwKa
[OH]=1014×0.22×105=1010=105
pOH=5
pH+pOH=14
So pH=145=9

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