The correct option is D pH=9;[OH]−=10−5M
NaBu + H2O ⇌ NaOH + BuH
Initial conc. 1 0 0
Conc. after hydrolysis 1−α α α
From hydrolysis of salt, we know,
[OH−]=Cα=C.√(KhC)=√(Kh.C)
=√[(KwKa).C],where,Kh=KwKa
[OH−]=√10−14×0.22×10−5=√10−10=10−5
pOH=5
pH+pOH=14
So pH=14−5=9