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Question

Ka for HCN is 5×1010 at 25 C. For maintaining a constant pH of 9, the volume of 5 M KCN solution required to be added to 10 mL of 2 M HCN solution is (log2=0.3 and log 5=0.69)

A
4 mL
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B
8 mL
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C
2 mL
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D
10 mL
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