Ka for the acid ionisation constant of Fe 3- and H - is 6-5- 10 -3- What is the maximum pH value which could be used so that at least 95

Fe ^ 3+ + H _ 2 O⇌ Fe( OH ) #160;^ 2+ + H ^ + K=[ Fe( OH ) #160;_ 2 ] #160;^ 2+ [ H ^ + ] #160;[ Fe ^ 3+ ] #160; = 5 100 ×[ H ^ + ] ...

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Electrochemical Series

Ka for the ac...

Question

$K_{a}$ for the acid ionisation constant of ${F e}^{3 +}$ and $H^{+}$ is $6.5 \times 10^{- 3}$ . What is the maximum pH value which could be used so that at least $95$ % of total ${F e}^{3 +}$ ion in solution exists free?

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K_{a}

F e^{3 +}

F e (O H)^{2 +}

H^{\oplus}

6.5 \times 10^{- 3}

F e^{3 +}

F e^{3 +}

{F e}^{3 +}

F e {(O H)}^{+ 2}

H^{+}

6.5 \times 10^{- 3}

p H

95

{F e}^{3 +}

{F e}^{3 +}

K_{a}

F e^{3 +} (a q .) + H_{2} O (l) ⇌ F e (O H)^{2 +} (a q .) + H_{3} O^{+} (a q .)

6.5 \times 10^{- 3}

p H

80 %

(I I I)

F e^{3 +}

{F e}^{3 +}

50 \times 10^{- 5} M

p H

99

{F e}^{3 +}

K_{{s p}_{F e {(O H)}_{3}}} = 10^{- 36}

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