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Kb aniline is...

Question

$K_{b}$ aniline is $10^{- 10}$ . A solution containing equal moles of aniline chloride will be:

basic

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neutral

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acidic

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cant predicted

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Solution

The correct option is C acidic
$p H = 14 - p K_{b} + log \frac{[b a s e]}{[s a l t]}$
$∴ [b a s e] = [s a l t] . . . g i v e n$
$∴ p H = 14 - p K_{b} = 14 - 10 = 4$
The solution is acidic.

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