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Basic Buffer Action

Kb for MeOH...

Question

$K_{b}$ for $M e O H$ an indicator is $10^{- 9}$ . The $p H$ at which it shows a colour change is

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Solution

$K_{b} = 10^{- 9}$
$p K_{b} = 9$
$p O H = p K_{b} + l o g \frac{S}{B}$
Color change will be observed when $l o g \frac{S}{B} = l o g 1 = 0$
$p O H = p K_{b} = 9$
$p H = 14 - p O H = 14 - 9 = 5$

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