K C for the reaction- A g - B g - C g - D g is 20 at 25- C- If a container contains 1-2-4-5 moles per litre of A g - B g - C g and D g respectively at 25- Cthen the reaction shall-A- Proceeds from left to rightB- Proceeds from right to leftC- Be at equilibriumD- None

The correct option is A Proceeds from left to rightQ = [C][D][A][B] = 4 × 51 × 2 = 10 K_c = 20 ∴ Q lt; K_c Therefore equilibrium will shift from left to ...

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Standard XII

Chemistry

Reaction Quotient

K C for the r...

Question

$K_{C}$ for the reaction,
$A_{(g)} + B_{(g)} ⇌ C_{(g)} + D_{(g)}$ is $20$ at $25^{\circ} C$ . If a container contains $1, 2, 4, 5$ moles per litre of $A_{(g)}, B_{(g)}, C_{(g)}$ and $D_{(g)}$ respectively at $25^{\circ} C$ , then the reaction shall:

Proceeds from left to right

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Proceeds from right to left

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Be at equilibrium

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None

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Solution

The correct option is A Proceeds from left to right
$Q = \frac{[C] [D]}{[A] [B]} = \frac{4 \times 5}{1 \times 2} = 10 K_{c} = 20 ∴ Q < K_{c}$
Therefore equilibrium will shift from left to right.

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KC for the reaction, A(g)+B(g)⇌C(g)+D(g) is 20 at 25 ∘C. If a container contains 1,2,4,5 moles per litre of A(g),B(g),C(g) and D(g) respectively at 25 ∘C, then the reaction shall:

The correct option is A Proceeds from left to rightQ=[C][D][A][B]=4×51×2=10Kc=20∴Q<Kc Therefore equilibrium will shift from left to right.

$K_{C}$ for the reaction,
$A_{(g)} + B_{(g)} ⇌ C_{(g)} + D_{(g)}$ is $20$ at $25^{\circ} C$ . If a container contains $1, 2, 4, 5$ moles per litre of $A_{(g)}, B_{(g)}, C_{(g)}$ and $D_{(g)}$ respectively at $25^{\circ} C$ , then the reaction shall:

The correct option is A Proceeds from left to right
$Q = \frac{[C] [D]}{[A] [B]} = \frac{4 \times 5}{1 \times 2} = 10 K_{c} = 20 ∴ Q < K_{c}$
Therefore equilibrium will shift from left to right.